Question

The electric field intensity on the surface of a solid charged sphere of radius 'r' and volume charge density '$\rho$' is ($\epsilon_0 =$ permittivity of free space)

• A. $\frac{\rho r}{3\epsilon_{0}}$
• B. $\frac{\rho}{4\pi\epsilon_{0}r}$
• C. zero
• D. $\frac{5\rho r}{6\epsilon_{0}}$

Hint:

Physics Tip: Inside a uniformly charged solid sphere, the electric field increases linearly with the distance from the center. On the surface, it reaches the value derived here.

Answer 1

The Correct Option is A