Step 1: Understanding the Concept
According to Gauss's Law, the total electric flux through any closed surface is proportional to the enclosed electric charge. For a spherical shell, we consider a Gaussian surface inside the shell.
Step 2: Detailed Explanation
1. A uniformly charged spherical shell has all its charge distributed on its outer surface.
2. If we take a Gaussian sphere of radius \(r<R\) (inside the shell), the total charge enclosed (\(q_{enclosed}\)) is exactly zero.
3. Applying Gauss's Law:
\[ \oint E \cdot dA = \frac{q_{enclosed}}{\epsilon_0} \]
4. Since \(q_{enclosed} = 0\), the electric field \(E\) must be zero at all points inside the shell.
Step 3: Final Answer
The electric field inside the shell is zero.