Question:medium

The electric field inside a uniformly charged spherical shell of radius \( R \) is:

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Inside a uniformly charged spherical shell, the electric field is always zero. This is a direct consequence of Gauss’s law and the symmetry of the problem.
Updated On: Apr 18, 2026
  • directly proportional to the charge within the shell
  • inversely proportional to \( R^2 \)
  • same as that outside the shell
  • zero
  • maximum at the centre
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
According to Gauss's Law, the total electric flux through any closed surface is proportional to the enclosed electric charge. For a spherical shell, we consider a Gaussian surface inside the shell.
Step 2: Detailed Explanation
1. A uniformly charged spherical shell has all its charge distributed on its outer surface. 2. If we take a Gaussian sphere of radius \(r<R\) (inside the shell), the total charge enclosed (\(q_{enclosed}\)) is exactly zero. 3. Applying Gauss's Law: \[ \oint E \cdot dA = \frac{q_{enclosed}}{\epsilon_0} \] 4. Since \(q_{enclosed} = 0\), the electric field \(E\) must be zero at all points inside the shell.
Step 3: Final Answer
The electric field inside the shell is zero.
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