Question:easy

The electric field in the region is \(\overset{⃗}{E} = a\hat{i}+b\hat{j}\) where 'a' and 'b' are constants. The net electric flux passing through a square area of side 'l' parallel to Y-Z plane is

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Only the component of E along the normal to the area gives flux.
Updated On: Oct 1, 2026
  • \(al\)
  • \(al^4\)
  • \(al^6\)
  • \(al^2\)
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The Correct Option is D

Solution and Explanation

Step 1: Component along the normal:
The normal to the Y-Z plane is $\hat i$. The field component along it is $a$.

Step 2: Multiply by area:
Area is $l\times l = l^2$, so $\Phi = a\times l^2$.

Step 3: Result:
$\Phi = al^2$, option (D).

Final Answer:
The flux is a l^2. \[ \boxed{\text{(D) }al^2} \]
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