To determine the expression for the magnetic field associated with a given electromagnetic wave, we need to consider the relationship between the electric and magnetic fields in an electromagnetic wave.
The electromagnetic wave is propagating in the x-direction, as indicated by the argument of the sine function in the given electric field expression:
E_y = 69 \sin(0.6 \times 10^3 x - 1.8 \times 10^{11} t) \, \text{V/m}
In a plane electromagnetic wave, the electric field E and the magnetic field B are mutually perpendicular and also perpendicular to the direction of wave propagation. This means:
Using the relationship between the electric and magnetic fields in an electromagnetic wave:
c = \frac{E}{B}
Where c\ is the speed of light in vacuum, approximately 3 \times 10^8 \, \text{m/s}.
Rearranging the equation, we find:
B = \frac{E}{c}
Substituting the given value of the electric field:
B_z = \frac{69 \, \text{V/m}}{3 \times 10^8 \, \text{m/s}} = 2.3 \times 10^{-7} \, \text{T}
Thus, the expression for the magnetic field associated with this electromagnetic wave is:
B_z = 2.3 \times 10^{-7} \sin(0.6 \times 10^3 x - 1.8 \times 10^{11} t) \, \text{T}
The correct answer is:
B_z = 2.3 \times 10^{-7} \sin(0.6 \times 10^3 x - 1.8 \times 10^{11} t)
This matches the options given, concluding that this option is the correct expression for the magnetic field.
The electric field of a plane electromagnetic wave, travelling in an unknown non-magnetic medium is given by,
\[ E_y = 20 \sin (3 \times 10^6 x - 4.5 \times 10^{14} t) \, \text{V/m} \] (where \(x\), \(t\) and other values have S.I. units). The dielectric constant of the medium is ____________.