Question:medium
The eigenvalues of a \(3\times3\) real matrix \(A\) are \(0\), \(-2\), \(-2\) and it satisfies the equation
\[
A^4+4A^3=KA^2,
\]
then the value of \(K\) is
The eigenvalues of a \(3\times3\) real matrix \(A\) are \(0\), \(-2\), \(-2\) and it satisfies the equation
\[
A^4+4A^3=KA^2,
\]
then the value of \(K\) is
Show Hint
If a matrix satisfies
\[
P(A)=0,
\]
then every eigenvalue \(\lambda\) satisfies
\[
\boxed{P(\lambda)=0.}
\]
Updated On: Jul 14, 2026
- \(-3\)
- \(-4\)
- \(3\)
- \(4\)
Show Solution
The Correct Option is B
Solution and Explanation
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