Question:medium
The eccentricity of the hyperbola \( \frac{(2x-6)^2}{2} - \frac{(4y+7)^2}{16} = 1 \) is
The eccentricity of the hyperbola \( \frac{(2x-6)^2}{2} - \frac{(4y+7)^2}{16} = 1 \) is
Show Hint
Always simplify coefficients properly before identifying \(a^2\) and \(b^2\).
Updated On: Apr 21, 2026
- \( \sqrt{5} \)
- \( \frac{\sqrt{5}}{2} \)
- \( \sqrt{3} \)
- \( \sqrt{10} \)
- \( \frac{\sqrt{3}}{2} \)
Show Solution
The Correct Option is C
Solution and Explanation
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