Question:medium

The eccentricity of the ellipse \(16x^2+7y^2=112\) is

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For an ellipse, first convert the equation into standard form. The larger denominator is \(a^2\), and eccentricity is \(e=\sqrt{1-\frac{b^2}{a^2}}\).
  • \(\frac{4}{3}\)
  • \(\frac{7}{16}\)
  • \(\frac{3}{\sqrt{7}}\)
  • \(\frac{3}{4}\)
Show Solution

The Correct Option is D

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