Step 1: Spot the conditions.
We have $f(x)=\frac{1}{\sqrt{x+|x|}}$. The square root needs its inside to be at least 0, and the denominator cannot be 0. Together, we need $x+|x|>0$.
Step 2: Test negative $x$.
If $x<0$, then $|x|=-x$, so $x+|x|=x-x=0$. That fails the strict greater-than-zero rule.
Step 3: Test $x=0$ and positive $x$.
At $x=0$ we again get $0$, which fails. If $x>0$, then $|x|=x$, so $x+|x|=2x>0$, which works.
Step 4: State the domain.
Only positive numbers work. \[ \boxed{(0,\infty)} \]