Question:medium
The domain of the function $f(x) = \begin{cases} \frac{x^2 - 9}{x - 3}, & \text{if } x \neq 3 \\ 6, & \text{if } x = 3 \end{cases}$ is:
The domain of the function $f(x) = \begin{cases} \frac{x^2 - 9}{x - 3}, & \text{if } x \neq 3 \\ 6, & \text{if } x = 3 \end{cases}$ is:
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A piecewise definition can remove discontinuities (holes).
Here, the undefined point at \( x=3 \) is filled by defining \( f(3)=6 \).
Updated On: May 2, 2026
- $(0, 3)$
- $(-\infty, 3)$
- $(-\infty, \infty)$
- $(3, \infty)$
- $(-3, 3)$
Show Solution
The Correct Option is C
Solution and Explanation
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