The distance between two consecutive points with phase difference of $60^{\circ}$ in a wave of frequency $n$ is $x$ meter. The velocity with which wave is traveling is

Question

A transverse wave along a string is given by $ y = 2 \sin \left( 2\pi (3t - x) + \frac{\pi{4} \right) $, where $ x $ and $ y $ are in cm and $ t $ in second. Find the acceleration of a particle located at $ x = 4 $ cm at $ t = 1 $ s.}

Answer 1

Step 1: Plan:
Use the phase formula $\Delta\phi = \frac{2\pi}{\lambda}\Delta x$.

Step 2: Steps:
$60^{\circ} = \frac{\pi}{3}$ rad. So $\frac{\pi}{3} = \frac{2\pi}{\lambda}x$, giving $\lambda = 6x$. Speed $v = n\lambda = 6nx$.

Final Answer:
The speed of the wave is $6nx$, option (D). \[ \boxed{6nx} \]

The distance between two consecutive points with phase difference of \(60^{\circ}\) in a wave of frequency \(n\) is \(x\) meter. The velocity with which wave is traveling is

Show Hint

The Correct Option is D

Solution and Explanation

Top Questions on Wave characteristics

Questions Asked in MHT CET exam