The distance between the parallel lines $5x + 12y - 3 = 0$ and $5x + 12y + 10 = 0$ is:
Show Hint
Since $(5, 12, 13)$ is a standard Pythagorean triplet, the denominator $\sqrt{5^2+12^2}$ is instantly $13$. The difference in constants is $10 - (-3) = 13$. The distance is simply $13/13 = 1$.