Question:medium

The discharge through a trapezoidal channel is maximum when

Show Hint

For the most efficient channel design:
- Trapezoidal: Sloping side = Half of top width. This simplifies to \(b = 2d\tan(\theta/2)\).
- Rectangular: Bed width is twice the depth of flow (\(b = 2d\)).
  • $b = 2d \tan \theta/2$
  • $d = 2b \tan \theta/2$
  • $d = 2b$
  • $b = 2d$
Show Solution

The Correct Option is A

Solution and Explanation

Was this answer helpful?
0