Question:medium

The disadvantage of Hopkinson's test on two dc shunt machines is

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Hopkinson's test requires two identical machines, which rules out option (2). Its main drawback lies in assuming that the stray losses (iron + mechanical losses) can be cleanly halved and shared equally between the motor and generator, ignoring the differences in field excitation.
Updated On: Jun 25, 2026
  • \( \text{copper and iron losses are assumed equal} \)
  • \( \text{requires two unidentical machines} \)
  • \( \text{iron and mechanical losses are assumed equal} \)
  • \( \text{iron and mechanical losses are assumed unequal} \)
Show Solution

The Correct Option is C

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