The direction ratios of a line \(L\) are \((ab,b,b)\) \((b\gt 0)\) and the line \(L\) passes through
\[
P(b,b,b).
\]
If \(Q(x,y,z)\) is a point on the line at a distance of \(b\) units from \(P\), then
\[
x+y+z=
\]
Show Hint
To find a point at a given distance along a line, first convert the direction ratios into a unit vector. Then use
\[
\text{New Point}
=
\text{Given Point}
\pm
(\text{Distance})\times(\text{Unit Vector}).
\]