Question:medium

The dimension of mutual inductance is (Denote dimension of current as A)

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Dimensional analysis is often easiest using energy formulas (\( \frac{1}{2}LI^2 \) or \( \frac{1}{2}CV^2 \)) as energy units are well-known.
Updated On: May 1, 2026
  • \( \text{M L}^2 \text{ T}^{-2} \text{ A}^{-2} \)
  • \( \text{M L}^2 \text{ T}^{-2} \text{ A}^{-2} \)
  • \( \text{M L}^{-2} \text{ T}^2 \text{ A}^{-2} \)
  • \( \text{M L}^2 \text{ T}^{-3} \text{ A}^{-1} \)
  • \( \text{M L}^2 \text{ T}^{-3} \text{ A}^{-3} \)
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The Correct Option is A

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