Question:medium

The difference between the maximum and minimum value of the function \[ f(x) = \int_{0}^{x} (t^2 + t + 1)\, dt \] on the interval \[ [2, 3] \] is: 

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If \( f'(x) > 0 \) on an interval, the function is increasing, so minimum occurs at left endpoint and maximum at right endpoint.
Updated On: May 1, 2026
  • \( \frac{39}{6} \)
  • \( \frac{49}{6} \)
  • \( \frac{59}{6} \)
  • \( \frac{69}{6} \)
  • \( \frac{79}{6} \)
Show Solution

The Correct Option is C

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