Given:
Diameter of zinc atom = 2.6 Å
1 Å = 10−10 m
Length = 1.6 cm = 1.6 × 10−2 m
(a) Radius of zinc atom
Radius = Diameter / 2
Radius = 2.6 / 2 = 1.3 Å
1 Å = 100 pm
Radius = 1.3 × 100 = 130 pm
(b) Number of atoms in 1.6 cm length
Diameter of one zinc atom = 2.6 Å = 2.6 × 10−10 m
Number of atoms = Total length / Diameter of one atom
Number of atoms = (1.6 × 10−2) / (2.6 × 10−10)
Number of atoms = 6.15 × 107
Final Answers:
(a) Radius of zinc atom = 130 pm
(b) Number of atoms in 1.6 cm = 6.15 × 107
Considering Bohr’s atomic model for hydrogen atom :
(A) the energy of H atom in ground state is same as energy of He+ ion in its first excited state.
(B) the energy of H atom in ground state is same as that for Li++ ion in its second excited state.
(C) the energy of H atom in its ground state is same as that of He+ ion for its ground state.
(D) the energy of He+ ion in its first excited state is same as that for Li++ ion in its ground state.