The derivative of \( 2^x \) is \( 2^x \log 2 \). The derivative of \( 3^x \) is \( 3^x \log 3 \). Therefore, the derivative of \( 2^x \) with respect to \( 3^x \) is \( \frac{2^x \log 2}{3^x \log 3} \). Final Answer: \( \boxed{ {(C)}} \)
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