Question

The de Broglie wavelength of a particle is:

• A. \(\frac{h}{p}\)
• B. \(\frac{p}{h}\)
• C. \(\frac{h^2}{p}\)
• D. \sqrt{\frac{h}{p}}

Hint:

The de Broglie wavelength is inversely proportional to momentum: \( \lambda = \frac{h}{p} \). Because Planck's constant \( h \) is extremely small, wave-like properties are only observable for subatomic particles with tiny masses, like electrons.

Answer 1

The Correct Option is A