Question

The de-Broglie wavelength ($\lambda$) of a particle is related to its kinetic energy ($E$) as

• A. $\lambda \propto E$
• B. $\lambda \propto E^{-1}$
• C. $\lambda \propto E^{\frac{1}{2}}$
• D. $\lambda \propto E^{-\frac{1}{2}}$

Hint:

Physics Tip: This relationship implies that if the kinetic energy of a particle increases, its associated de-Broglie wavelength decreases.

Answer 1

The Correct Option is D