Question

The currents in different parts of the electric circuit are shown in following figure. The value of current \(i\) is

• A. \(0.7\) A
• B. \(1.4\) A
• C. \(2.1\) A
• D. \(2.8\) A

Hint:

Current entering a junction equals current leaving it.

Answer 1

The Correct Option is C

Step 1: Approach
Apply the law to the whole network at once.

Step 2: Totals
Total current in = $2+3=5$ A. Total current out = $1+0.6+1.3+i$.

Step 3: Equate
$5=2.9+i$, so $i=2.1$ A. Option (C).

Final Answer:
The currents in total are 5 A and the known outflows are 2.9 A, so i = 2.1 A, option (C). \[ \boxed{2.1\ \text{A}} \]