Question

The current passing through the galvanometer is 4 % of the total current in the curcuit. If the resistance of the galvanometer is 'G', the shunt resistance 'S' connected across the galvanometer is

• A. \(25\,G\)
• B. \(24\,G\)
• C. \(\frac{G}{24}\)
• D. \(\frac{G}{25}\)

Hint:

The potential gradient is the potential difference divided by the wire length.

Answer 1

The Correct Option is C

Step 1: Fraction of the wire:
The balancing length is $\frac{80}{400} = \frac15$ of the wire.

Step 2: Voltage:
So the emf is $\frac15\times2 = 0.4$ V (C).

Final Answer:
0.4 V. \[ \boxed{0.4\text{ V}} \]