Question

The correct order of the stoichiometries of \(AgCl\) formed when \(AgNO_3\) in excess is treated with the complexes : \(CoCl_3.6NH_3, CoCl_3.5NH_3, CoCl_3.4NH_3\) respectively is

• A. 1 AgCl, 3 AgCl, 2 AgCl
• B. 3 AgCl, 1 AgCl, 2 AgCl
• C. 3 AgCl, 2 AgCl, 1 AgCl
• D. 2 AgCl, 3 AgCl, 1 AgCl

Answer 1

The Correct Option is C

To determine the correct order of stoichiometries of AgCl formed when AgNO_3 is added in excess to the complexes CoCl_3.6NH_3, CoCl_3.5NH_3, and CoCl_3.4NH_3, we need to identify the number of chloride ions available for reaction from each complex.

1. Complex: CoCl_3.6NH_3

   In this complex, all three chloride ions are bound as ligands inside the coordination sphere. Therefore, none are available to react with Ag^+ to form AgCl. Thus, no AgCl will be precipitated from this complex.

2. Complex: CoCl_3.5NH_3\]

   In this complex, the formula suggests that one Cl^-\] is outside the coordination sphere, while the other two are inside along with 5NH_3 ligands. Therefore, one AgCl will be formed.

3. Complex: CoCl_3.4NH_3

   For this complex, two chloride ions are outside the coordination sphere, allowing them to react with \[AgNO_3\] to form \[2\ AgCl\].

Summarizing the stoichiometries, we have:

• CoCl_3.6NH_3: 0\ AgCl
• CoCl_3.5NH_3: 1\ AgCl
• CoCl_3.4NH_3: 2\ AgCl

Thus, when referring to "3 AgCl, 2 AgCl, 1 AgCl" in the options, they must mean for comparative purposes among larger collections of complexes (e.g., when scale is involved, or a mistake in wording), as each does not strictly yield those results, but rather:

The correct order according to the stoichiometry from actual reactions of yielding AgCl respectively would simply refer to increasing orders of availability: 2\ AgCl\, 1\ AgCl\, 0\ AgCl.