Question:medium
The correct order of stability for the following carbanions is:
\[
\text{CH}_2=\text{CH}^- ,\quad \text{CH}_3-\text{CH}_2^- ,\quad \text{CH}\equiv\text{C}^-
\]
The correct order of stability for the following carbanions is:
\[
\text{CH}_2=\text{CH}^- ,\quad \text{CH}_3-\text{CH}_2^- ,\quad \text{CH}\equiv\text{C}^-
\]
Show Hint
For carbanions, stability increases with increasing \(s\)-character of the hybrid orbital holding the negative charge.
Updated On: Apr 1, 2026
- \(\text{CH}=\text{C}^->\text{CH}_2=\text{CH}^->\text{CH}_3-\text{CH}_2^-\)
- \(\text{CH}_3-\text{CH}_2^->\text{CH}_2=\text{CH}^->\text{CH}\equiv\text{C}^-\)
- \(\text{CH}_2=\text{CH}^->\text{CH}\equiv\text{C}^->\text{CH}_3-\text{CH}_2^-\)
- \(\text{CH}\equiv\text{C}^->\text{CH}_3-\text{CH}_2^->\text{CH}_2=\text{CH}^-\)
Show Solution
The Correct Option is A
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