Question:medium

The correct order of increasing boiling points of the following compounds is: Pentan-1-ol, n-Butane, Pentanal, Ethoxyethane

Updated On: Jan 16, 2026
  • Ethoxyethane, Pentanal, n-Butane, Pentan-1-ol
  • Pentanal, n-Butane, Ethoxyethane, Pentan-1-ol
  • n-Butane, Pentanal, Ethoxyethane, Pentan-1-ol
  • n-Butane, Ethoxyethane, Pentanal, Pentan-1-ol
Show Solution

The Correct Option is D

Solution and Explanation

To establish the ascending order of boiling points for n-Butane, Ethoxyethane (Diethyl ether), Pentanal, and Pentan-1-ol, an analysis of their intermolecular forces—Van der Waals forces, dipole-dipole interactions, and hydrogen bonding—is necessary.

  • n-Butane: Being an alkane, it exhibits only weak Van der Waals forces, lacking substantial dipole moments or hydrogen bonding capacity, thus possessing a low boiling point.
  • Ethoxyethane (Diethyl ether): It displays stronger Van der Waals forces than n-butane and engages in dipole-dipole interactions due to its ether functional group, resulting in a higher boiling point than n-butane.
  • Pentanal: As an aldehyde, its polar carbonyl group facilitates stronger dipole-dipole interactions than ethoxyethane, leading to a higher boiling point compared to ethoxyethane.
  • Pentan-1-ol: The presence of a hydroxyl group (-OH) enables hydrogen bonding, a force that significantly elevates its boiling point above that of the other compounds.

Consequently, the sequence of increasing boiling points is: n-Butane, Ethoxyethane, Pentanal, Pentan-1-ol.

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