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The coordinates of the focus and the vertex of a parabola, respectively, are $(-1,\,4)$ and $(3,\,4)$. Then the equation of the parabola is
The coordinates of the focus and the vertex of a parabola, respectively, are $(-1,\,4)$ and $(3,\,4)$. Then the equation of the parabola is
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If the focus and vertex have the same $y$-coordinate, the parabola is horizontal. If focus is left of vertex, it opens left: $(y-k)^2 = -4a(x-h)$. If focus is right, it opens right: $(y-k)^2 = 4a(x-h)$.
Updated On: Apr 25, 2026
- $(x-3)^2 = 16(y-4)$
- $(x-3)^2 = -16(y-4)$
- $(y-4)^2 = -8(x-3)$
- $(y-4)^2 = -16(x-3)$
- $(y-4)^2 = 1(x-3)$
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The Correct Option is D
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