Question

The compound forming ccp structure contains $9.6\times10^{23}$ atoms. Find the number of tetrahedral voids formed in it.

• A. $1.00\times10^{24}$
• B. $1.68\times10^{24}$
• C. $1.92\times10^{24}$
• D. $1.56\times10^{24}$

Hint:

For $N$ packing atoms: Tetrahedral Voids = $2N$, Octahedral Voids = $N$. Therefore, the total number of voids combined is $3N$!

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
In any close-packed structure (ccp or hcp), if the number of atoms is $N$, the number of octahedral voids is $N$ and the number of tetrahedral voids is $2N$.

Step 2: Formula Application:
Number of Tetrahedral Voids = $2 \times (\text{Number of atoms})$

Step 3: Explanation:
Given atoms $N = 9.6 \times 10^{23}$. Tetrahedral voids = $2 \times 9.6 \times 10^{23} = 19.2 \times 10^{23} = 1.92 \times 10^{24}$.

Step 4: Final Answer:
The number of tetrahedral voids is $1.92 \times 10^{24}$.