The compound C₇H₈ undergoes the following reactions :

The product ‘C’ is

Question

The reagent used in the Etard reaction is:

Answer 1

Given the compound C₇H₈, which is toluene, undergoes the following sequence of reactions:

Let's analyze each step in the reaction sequence:

The first step involves the reaction of toluene with 3 equivalents of Cl₂ in the presence of heat (Δ). This is a free radical chlorination reaction that primarily occurs at the methyl group, resulting in a trichloromethyl group forming a compound of the structure C₆H₅-CCl₃ (benzylic trichloride, compound A).
In the second step, compound A reacts with Br₂ in the presence of Fe to substitute one hydrogen atom in the benzene ring. This results in bromination at the meta position with respect to the trichloromethyl group, leading to m-bromo benzyl trichloride (compound B).
For the third step, compound B is treated with Zn/HCl, which reduces the trichloromethyl group back to a methyl group, while the meta substitution of bromine is retained, forming m-bromotoluene (compound C).

Hence, the final product ‘C’ formed is m-bromotoluene.

Thus, the correct answer is:

m-bromotoluene

Answer 2

Given the compound C₇H₈, which is toluene, undergoes the following sequence of reactions:

Let's analyze each step in the reaction sequence:

The first step involves the reaction of toluene with 3 equivalents of Cl₂ in the presence of heat (Δ). This is a free radical chlorination reaction that primarily occurs at the methyl group, resulting in a trichloromethyl group forming a compound of the structure C₆H₅-CCl₃ (benzylic trichloride, compound A).
In the second step, compound A reacts with Br₂ in the presence of Fe to substitute one hydrogen atom in the benzene ring. This results in bromination at the meta position with respect to the trichloromethyl group, leading to m-bromo benzyl trichloride (compound B).
For the third step, compound B is treated with Zn/HCl, which reduces the trichloromethyl group back to a methyl group, while the meta substitution of bromine is retained, forming m-bromotoluene (compound C).

Hence, the final product ‘C’ formed is m-bromotoluene.

Thus, the correct answer is:

m-bromotoluene

The Correct Option is A