Question

The compound A on treatment with Na gives B, and with PCl₅ gives C. B and C react together to give diethyl ether. A, B and C are in the order

• A. C₂H₅OH, C₂H₆ , C₂H₅Cl
• B. C₂H₅Cl, C₂H₆ , C₂H₅OH
• C. C₂H₅OH, C₂H₅Cl, C₂H₅ONa
• D. C₂H₅OH, C₂H₅ONa, C₂H₅Cl

Answer 1

The Correct Option is D

The question involves determining the correct order of the compounds A, B, and C, based on their reactions and final product. Let's analyze the given reactions:

1. Compound A reacts with Na to form B. The typical reaction of an alcohol with sodium (Na) produces an alkoxide. Ethanol (C₂H₅OH) reacts with Na to give ethoxide (C₂H₅ONa). Therefore, A is C₂H₅OH, and B is C₂H₅ONa.
2. Compound A (C₂H₅OH) reacts with PCl₅ to form chloroethane (C₂H₅Cl), which is compound C. This is a known reaction where an alcohol reacts with PCl₅ to form an alkyl chloride.
3. Compounds B (C₂H₅ONa) and C (C₂H₅Cl) react together. An alkoxide (ethoxide) can react with an alkyl halide (chloroethane) to form an ether (diethyl ether in this case, C₂H₅OC₂H₅).

Based on this analysis, the correct order of the compounds A, B, and C is:

• A: C₂H₅OH
• B: C₂H₅ONa
• C: C₂H₅Cl

This matches with the answer option: C₂H₅OH, C₂H₅ONa, C₂H₅Cl. Let's briefly justify why other options are incorrect:

• For the option C₂H₅OH, C₂H₆, C₂H₅Cl: B cannot be C₂H₆ as it wouldn’t form diethyl ether with C₂H₅Cl.
• For the option C₂H₅Cl, C₂H₆, C₂H₅OH: B and C are incorrectly positioned, and C₂H₅Cl should not be the alcohol reacting initially.
• For the option C₂H₅OH, C₂H₅Cl, C₂H₅ONa: B and C are incorrectly listed, as C₂H₅Cl is formed from A with PCl₅, not from Na.

Thus, the confirmed and correct answer is: C₂H₅OH, C₂H₅ONa, C₂H₅Cl.