Question:medium

The compound $A$, C$_8$H$_8$O$_2$, reacts with acetophenone to form a single product via cross-aldol condensation. The compound $A$ on reaction with conc. NaOH forms a substituted benzyl alcohol as one of the two products. The compound $A$ is:

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Cannizzaro reaction is shown only by aldehydes without $\alpha$-hydrogen, producing alcohol and acid as products.
Updated On: Feb 24, 2026
  • 4-methyl benzoic acid
  • 2-hydroxy acetophenone
  • 4-hydroxy benzylaldehyde
  • 4-methoxy benzaldehyde
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The Correct Option is A

Solution and Explanation

The given compound \( A \) has the formula \( \text{C}_8\text{H}_8\text{O}_2 \). An important clue is that it undergoes cross-aldol condensation with acetophenone. Also, on reaction with concentrated NaOH, it forms a substituted benzyl alcohol as one of the two products.

Cross-aldol condensation generally involves compounds with aldehyde or ketone groups. Among the given options, let's analyze each:

  1. 4-methyl benzoic acid: This option is a carboxylic acid. Carboxylic acids do not typically undergo aldol condensation due to the lack of a carbonyl carbon that can participate in such reactions. Thus, this is unlikely to be \( A \).
  2. 2-hydroxy acetophenone: This compound has a ketone group and an aromatic ring. It can participate in cross-aldol condensation, but the structural formula \( \text{C}_8\text{H}_8\text{O}_2 \) may not match well with this compound.
  3. 4-hydroxy benzylaldehyde: This compound carries an aldehyde group, making it a good candidate for aldol condensation. Additionally, when reacted with concentrated NaOH (a condition often related to Cannizzaro reaction), it can yield benzyl alcohol derivatives, matching with the fact it forms a substituted benzyl alcohol. The molecular formula fits as well.
  4. 4-methoxy benzaldehyde: Like the previous option, this compound can undergo aldol condensation. However, as there is no substituent that resembles a benzyl alcohol formation upon reaction with NaOH, this can be ruled out.

The correct compound \( A \) therefore aligns well with 4-hydroxy benzylaldehyde because:

  • The molecular formula \( \text{C}_8\text{H}_8\text{O}_2 \) fits perfectly.
  • It can undergo cross-aldol condensation due to the presence of an aldehyde group.
  • The reaction with concentrated NaOH gives rise to substituted benzyl alcohol as a product, which aligns with the reaction conditions like Cannizzaro reaction.

Hence, the correct answer is 4-hydroxy benzylaldehyde.

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