Question:medium

The complex $[Cr(NH_3)_4Cl_2]^+$ shows how many geometrical isomers?

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For octahedral complexes of the type $[MA_4B_2]$, only cis and trans forms are possible geometrical isomers.
Updated On: Jan 13, 2026
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The Correct Option is B

Solution and Explanation

The octahedral complex [Cr(NH3)4Cl2]+ features four ammonia (NH3) ligands and two chloride (Cl) ligands. Octahedral complexes display geometrical isomerism when at least two distinct ligand types bind to the metal center. This complex, containing NH3 and Cl ligands, exhibits two possible isomers based on the spatial arrangement of the Cl ligands:
  • Cis isomer: The two Cl ligands are positioned adjacent to each other in the octahedral structure.
  • Trans isomer: The two Cl ligands are positioned opposite each other in the octahedral structure.
Consequently, the [Cr(NH3)4Cl2]+ complex can exist as 2 geometrical isomers: cis and trans.
Geometrical Isomers
Cis
Trans
In summary, the complex exhibits 2 geometrical isomers.
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