The coil of an a.c. generator has 100 turns, each of cross-sectional area $2 \text{ m}^2$. It is rotating at constant angular speed $30 \text{ rad/s}$, in a uniform magnetic field of $2\times10^{-2}\text{ T}$. If the total resistance of the circuit is 600 $\Omega$ then maximum power dissipated in the circuit is
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Logic Tip: You can bypass calculating the current by directly using the formula $P_{avg} = \frac{E_0^2}{2R}$. Substituting the values directly gives $P = \frac{(120)^2}{2 \times 600} = \frac{14400}{1200} = 12 \text{ W}$.