Question:medium

The coefficient of \( x^2 \) in the expansion of the determinant \( \begin{vmatrix} x^2 & x^3+1 & x^5+2 \\ x^3+3 & x^2+x & x^3+x^4 \\ x+4 & x^3+x^5 & 2^3 \end{vmatrix} \) is:

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To find the coefficient of $x^n$ in a determinant, you can differentiate the determinant $n$ times using the rule of differentiating rows/columns and evaluate at $x=0$, then divide by $n!$.
Updated On: May 2, 2026
  • $-10$
  • $-8$
  • $-2$
  • $-6$
  • $8$
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The Correct Option is A

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