Question

The code given below accepts five numbers and displays whether they are even or odd: 
Observe the following code carefully and rewrite it after removing all syntax and logical errors. 
Underline all the corrections made.

Hint:

Always check for syntax errors (e.g., missing colons or parentheses) and ensure the correct operators are used for logical conditions (e.g., `%` for even/odd checks).

Answer 1

Initial Code:

def EvenOdd()
    for i in range(5):
        num=int(input("Enter a number"
        if num/2==0:
            print("Even")
        else:
            print("Odd")
EvenOdd()
    

Refined Code:

def EvenOdd():  # Colon added to function definition
    for i in range(5):  # No modification
        num = int(input("Enter a number: "))  # Colon and closing parenthesis added to input
        if num % 2 == 0:  # Division '/' replaced with modulus '%' for parity check
            print("Even")  # No modification
        else:
            print("Odd")  # No modification
EvenOdd()  # No modification
    

Modifications Implemented:

• A colon : was appended to the function definition def EvenOdd().
• The incomplete input statement was rectified to input("Enter a number: ") by adding a colon and closing the parenthesis.
• The condition for checking even numbers was updated from if num / 2 == 0 to if num % 2 == 0 by substituting the division operator / with the modulus operator %.