Step 1: Understanding the Concept:
Factorize the pair of lines to identify the vertices of the triangle.
Step 2: Formula Application:
$xy + 2x + 2y + 4 = (x+2)(y+2) = 0$.
The lines are $x = -2$ and $y = -2$.
Step 3: Explanation:
The three lines are $x = -2$, $y = -2$, and $x + y = -2$.
- Intersection of $x=-2$ and $y=-2$ is $V_1(-2, -2)$.
- Intersection of $x=-2$ and $x+y=-2$ is $V_2(-2, 0)$.
- Intersection of $y=-2$ and $x+y=-2$ is $V_3(0, -2)$.
This is a right-angled triangle at $(-2, -2)$. In a right-angled triangle, the circumcenter is the midpoint of the hypotenuse.
Midpoint of $V_2V_3 = \left( \frac{-2+0}{2}, \frac{0-2}{2} \right) = (-1, -1)$.
Step 4: Final Answer:
The circumcenter is (-1, -1).