Question

The calculated magnetic moment of two dipositive ions of 3d series element is 4.9 BM. The ions are

• A. \(Ti^{2+}\) and \(Sc^{2+}\)
• B. \(Mn^{2+}\) and \(Cr^{2+}\)
• C. \(V^{2+}\) and \(Ti^{2+}\)
• D. \(Cr^{2+}\) and \(Fe^{2+}\)
• E. \(Fe^{2+}\) and \(Ni^{2+}\)

Hint:

A quick shortcut: The magnetic moment value X.Y usually implies there are X unpaired electrons.
So, \(4.9 \text{ BM} \implies 4\) unpaired electrons.

Answer 1

The Correct Option is D