Question

The bond dissociation energy of X\(_2\), Y\(_2\) and XY are in the ratio of 1 : 0.5 : 1. \(\Delta H\) for the formation of XY is -200 kJ/mol. The bond dissociation energy of X\(_2\) will be

• A. 200 kJ/mol
• B. 100 kJ/mol
• C. 400 kJ/mol
• D. 800 kJ/mol

Hint:

The bond dissociation energy of a molecule is the energy required to break the bond between two atoms in a molecule.

Answer 1

The Correct Option is D

Step 1: Given Data
Let the bond dissociation energy of X\(_2\) be \(a\) kJ/mol. The bond dissociation energy of Y\(_2\) is \(0.5a\) kJ/mol, and the bond dissociation energy of XY is \(a\) kJ/mol.The formation reaction is: \[\frac{1}{2} {X}_2 + \frac{1}{2} {Y}_2 \rightarrow {XY}, \, \Delta H = -200 \, {kJ/mol}\]Step 2: Bond Energy Calculation
The enthalpy change can be calculated using bond energies: \[\Delta H = BE({Reactants}) - BE({Products})\]\[\Delta H = \left[\frac{1}{2} \, BE({X}_2) + \frac{1}{2} \, BE({Y}_2)\right] - BE({XY})\]Substituting the given values: \[\Delta H = \left[\frac{a}{2} + \frac{0.5a}{2}\right] - a\]\[-200 = \frac{a + 0.5a}{2} - a\]\[-200 = \frac{1.5a}{2} - a\]\[-200 = 0.75a - a\]\[-200 = -0.25a\]Solving for \(a\): \[a = 800 \, {kJ/mol}\]Therefore, the correct answer is (D).