Question

The bob of a simple pendulum of length 'L' is released from a position of small angular displacement $\theta$. Its linear displacement at time 't' is ($g =$ acceleration due to gravity)

• A. $L\theta \cos \left[ \sqrt{\frac{g}{L}} \cdot t \right]$
• B. $L\theta \sin \left[ 2\pi\sqrt{\frac{g}{L}} \cdot t \right]$
• C. $L\theta \cos \left[ 2\pi\sqrt{\frac{g}{L}} \cdot t \right]$
• D. $L\theta \sin \left[ \sqrt{\frac{g}{L}} \cdot t \right]$

Hint:

Physics Tip : The $\cos$ function is used here because the motion begins at the maximum displacement (the extreme position) at $t=0$.

Answer 1

The Correct Option is A