Step 1: Reason with Impurities
A p-type semiconductor has acceptor levels close to the valence band, so $E_F$ moves towards V.
Step 2: n-type and Intrinsic
An n-type semiconductor has donor levels close to the conduction band, so $E_F$ moves towards C. An intrinsic one has $E_F$ at the centre of the gap.
Step 3: Match the Options
Figure (2) is p, figure (1) is intrinsic and figure (3) is n, matching the second option.
Final Answer:
The order p, intrinsic, n is the correct match.
\[ \boxed{\text{(B) }\text{p, intrinsic and n}} \]