Question:medium
The axis of the parabola \( x^2 + 6x + 4y + 5 = 0 \) is:
The axis of the parabola \( x^2 + 6x + 4y + 5 = 0 \) is:
Show Hint
For parabolas with only \(x^2\), always complete the square in \(x\).
The axis of symmetry is directly given by \( x = -\frac{D}{2} \) from \( x^2 + Dx \).
Updated On: Apr 30, 2026
- \( x = 0 \)
- \( y = 1 \)
- \( x + 3 = 0 \)
- \( y = 4 \)
- \( y + 2 = 0 \)
Show Solution
The Correct Option is C
Solution and Explanation
Was this answer helpful?
0
Top Questions on sections of a cone
- If the line 2x-1=0 is the directrix of the parabola y²-kx+6=0, then one of the values of k is
- BITSAT - 2010
- Mathematics
- sections of a cone
- The line ax+by=1 cuts ellipse cx²+dy²=1 only once if
- BITSAT - 2010
- Mathematics
- sections of a cone
- The length of the latus-rectum of the parabola whose focus is ((u²)/(2g)\sin2α,-(u²)/(2g)\cos2α) and directrix is y=(u²)/(2g), is:
- BITSAT - 2011
- Mathematics
- sections of a cone
- The equation of the ellipse with focus at (±5,0) and eccentricity =(5)/(6) is:
- BITSAT - 2011
- Mathematics
- sections of a cone
- Want to practice more? Try solving extra ecology questions todayView All Questions
