The average of 5 numbers is 27. If one of the numbers, 35, is removed, what is the average of the remaining four?

Question

Average of 5 integers is 38 and all the numbers are between 0 and 50 (both inclusive). In these 5 numbers, a is the minimum. If exactly 3 of them are more than 32, find the difference between the minimum and the maximum value of a.

Answer 1

The removed value 35 is 8 above the old mean of 27, and that surplus of 8 spread over the remaining 4 lowers the mean by $\dfrac{8}{4} = 2$, giving $27 - 2 = 25$.

The average of 5 numbers is 27. If one of the numbers, 35, is removed, what is the average of the remaining four?

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The Correct Option is A

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