Question:medium
The area of the parallelogram with vertices \( (0, 0), (7, 2), (5, 9) \) and \( (12, 11) \) is:
The area of the parallelogram with vertices \( (0, 0), (7, 2), (5, 9) \) and \( (12, 11) \) is:
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For any parallelogram \( ABCD \), the area is twice the area of triangle \( ABC \). Using the determinant method directly on the vectors from the origin is the fastest way to solve coordinate-based area problems.
Updated On: May 1, 2026
- \( 50 \)
- \( 54 \)
- \( 51 \)
- \( 52 \)
- \( 53 \)
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The Correct Option is
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