The annual profit of a company depends on its annual marketing expenditure. The information of preceding 3 years' annual profit and marketing expenditure is given in the table. Based on linear regression, the estimated profit (in units) of the 4superscript{th year at a marketing expenditure of 5 units is ............ (Rounded off to two decimal places)} 
To estimate the annual profit using linear regression, we need to find the linear relationship between marketing expenditure (x) and annual profit (y). The data is:
| Year | Expenditure (x) | Profit (y) |
|---|---|---|
| 1 | 3 | 22 |
| 2 | 4 | 27 |
| 3 | 6 | 36 |
We use the formula for the regression line: y = mx + c.
Calculate the slope (m) and intercept (c):
\( m = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \)
Substituting in the formula:
\( m = \frac{3(390) - 13(85)}{3(61) - 13^2} = \frac{1170 - 1105}{183 - 169} = \frac{65}{14} \approx 4.64 \)
Calculate the intercept (c):
\( c = \frac{\sum y - m \sum x}{n} = \frac{85 - 4.64 \times 13}{3} = \frac{85 - 60.32}{3} \approx 8.23 \)
Regression line: \( y = 4.64x + 8.23 \).
Substitute x = 5 to estimate the profit:
\( y = 4.64(5) + 8.23 = 23.2 + 8.23 = 31.43 \)
The estimated profit for a marketing expenditure of 5 units is 31.43 units.
The range given is 30.30. The estimated profit of 31.43 falls within the acceptable range.
Let \[ A = \begin{bmatrix} 1 & 1 & 1 \\ 1 & 3 & 1 \\ -2 & -3 & -3 \end{bmatrix}, \quad b = \begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix}. \] For \( Ax = b \) to be solvable, which one of the following options is the correct condition on \( b_1, b_2, \) and \( b_3 \)?
Which model is represented by the following graph?
