Question:medium

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

Updated On: Jan 13, 2026
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Solution and Explanation

The angle of elevation of the top of a tower from a point on the ground
Consider a tower AB. The angle of elevation from a ground point C is 30°.

In right-angled triangle ABC,

\(\frac{AB}{ BC} = tan 30°\)

Given BC = 30 m, we have:

\(\frac{AB}{ 30 }= \frac{1}{ \sqrt3}\)

\(AB = \frac{30}{ \sqrt3} = 10\sqrt3\,m\)

The height of the tower is thus \(10\sqrt3\,m\).

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