
Consider a tower AB. The angle of elevation from a ground point C is 30°.
In right-angled triangle ABC,
\(\frac{AB}{ BC} = tan 30°\)
Given BC = 30 m, we have:
\(\frac{AB}{ 30 }= \frac{1}{ \sqrt3}\)
\(AB = \frac{30}{ \sqrt3} = 10\sqrt3\,m\)
The height of the tower is thus \(10\sqrt3\,m\).