Question:medium
The angle between the straight lines \( x - 1 = \frac{2y + 3}{3} = \frac{z + 5}{2} \) and \( x = 3r + 2; y = -2r - 1; z = 2 \), where \( r \) is a parameter, is:
The angle between the straight lines \( x - 1 = \frac{2y + 3}{3} = \frac{z + 5}{2} \) and \( x = 3r + 2; y = -2r - 1; z = 2 \), where \( r \) is a parameter, is:
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Always normalize the coefficients of $x, y,$ and $z$ to 1 in symmetric equations before identifying direction ratios. A common trap is having $2y$ instead of $y$.
Updated On: May 6, 2026
- \( \frac{\pi}{4} \)
- \( \cos^{-1}\left(\frac{-3}{\sqrt{182}}\right) \)
- \( \sin^{-1}\left(\frac{-3}{\sqrt{182}}\right) \)
- \( \frac{\pi}{2} \)
- \( 0 \)
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The Correct Option is D
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