Question:medium
The angle between a normal to the plane \( 2x - y + 2z - 1 = 0 \) and the \( z \)-axis is:
The angle between a normal to the plane \( 2x - y + 2z - 1 = 0 \) and the \( z \)-axis is:
Show Hint
The angle between a vector and any coordinate axis is determined simply by the direction cosine of that vector for that specific axis. Here, the direction cosine for the $z$-axis is $C / |\vec{n}|$.
Updated On: May 6, 2026
- \( \cos^{-1}\left(\frac{1}{3}\right) \)
- \( \sin^{-1}\left(\frac{2}{3}\right) \)
- \( \cos^{-1}\left(\frac{2}{3}\right) \)
- \( \sin^{-1}\left(\frac{1}{3}\right) \)
- \( \sin^{-1}\left(\frac{3}{5}\right) \)
Show Solution
The Correct Option is C
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