Question:medium

The amount of silver in mg deposited when \(9.65\) coulombs of electricity is passed through an aqueous solution of silver nitrate is \(\left(Ag=108u,\ 1F=96500\text{ C mol}^{-1}\right)\)

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Use Faraday's law: \(m=\frac{EQ}{F}\). For silver, equivalent weight is \(108\).
  • \(16.2\)
  • \(21.2\)
  • \(10.8\)
  • \(6.4\)
Show Solution

The Correct Option is C

Solution and Explanation

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