To determine which alkane gives only one mono-chloro product upon chlorination with Cl_2 in the presence of diffused sunlight, we must understand the structure of the alkanes provided in the options.
Understanding mono-chlorination:
Mono-chlorination refers to the replacement of one hydrogen atom in the alkane with a chlorine atom. The ability of an alkane to form only one mono-chloro product depends on the equivalence of the hydrogen atoms in the molecule.
Analyzing the options:
2,2-dimethylbutane: This hydrocarbon has multiple types of hydrogen atoms due to its branching, leading to more than one type of mono-chloro product.
Neopentane (2,2-dimethylpropane): This molecule is symmetrical, meaning all hydrogen atoms are equivalent. Therefore, chlorination will replace any hydrogen to give the same mono-chloro product.
n-pentane: This straight-chain alkane has multiple types of hydrogen (primary and secondary), leading to different mono-chloro products.
Isopentane (2-methylbutane): This compound also has non-equivalent hydrogen atoms due to branching, producing different mono-chloro products.
Conclusion: Neopentane gives only one type of mono-chloro product because of its symmetrical structure where all the hydrogen atoms are equivalent. Therefore, neopentane is the correct answer.