The enthalpy of neutralisation is the heat change that occurs when one mole of water is formed by the reaction of an acid with a base. The reaction provided in the question is:
\text{MgO}_{(s)} + 2\text{HCl}_{(aq)} \rightarrow \text{MgCl}_2_{(aq)} + \text{H}_2\text{O}_{(l)}
In this reaction, magnesium oxide (MgO) reacts with hydrochloric acid (HCl) to form magnesium chloride (MgCl2) and water (H2O).
For a typical acid-base neutralization reaction involving strong acids and bases, the enthalpy change is usually around -57.33 kJ mol-1. However, MgO is a solid oxide, and its reaction with HCl involves not only neutralization but also the dissolution of MgO into MgCl2 ions. This process requires additional energy, making the overall enthalpy change less negative.
Thus, for the given reaction of MgO with HCl, the absolute enthalpy of neutralization will be:
Hence, the reaction of MgO with HCl will have an enthalpy change less negative than -57.33 kJ mol-1 because it is not a simple acid-base reaction but involves an additional dissolution process.
A real gas within a closed chamber at \( 27^\circ \text{C} \) undergoes the cyclic process as shown in the figure. The gas obeys the equation \( PV^3 = RT \) for the path A to B. The net work done in the complete cycle is (assuming \( R = 8 \, \text{J/molK} \)):
