Question:medium

$\textbf{Match List I with List II}$
$\begin{array}{|c|c|c|} \hline \text{List I (Bio Polymer)} & \text{List II (Monomer)} \\ \hline \text{A. Starch} & \text{I. nucleotide} \\ \text{B. Cellulose} & \text{II. } \alpha\text{-glucose} \\ \text{C. Nucleic acid} & \text{III. } \beta\text{-glucose} \\ \text{D. Protein} & \text{IV. } \alpha\text{-amino acid} \\ \hline \end{array}$
$\text{Choose the correct answer from the options given below :-}$

Updated On: Feb 4, 2026
  • A-II, B-I, C-III, D-IV
  • A-IV, B-II, C-I, D-III
  • A-I, B-III, C-IV, D-II
  • A-II, B-III, C-I, D-IV
Show Solution

The Correct Option is D

Solution and Explanation

To address the question, each biopolymer in List I must be correctly paired with its corresponding monomer from List II.

  1. Starch: Starch, a polysaccharide, is formed from \(\alpha\)-glucose units. This aligns with option II, α-glucose.
  2. Cellulose: Cellulose is another polysaccharide, constructed from \(\beta\)-glucose monomers. Consequently, it matches option III, β-glucose.
  3. Nucleic Acid: Nucleic acids (e.g., DNA, RNA) are polymers of nucleotides. Therefore, the correct pairing is with option I, nucleotide.
  4. Protein: Proteins are synthesized from chains of amino acids, specifically \(\alpha\)-amino acids. This corresponds to option IV, α-amino acid.

Based on these pairings, the correct selection is: A-II, B-III, C-I, D-IV.

List I (Bio Polymer)List II (Monomer)
A. StarchII. \(\alpha\)-glucose
B. CelluloseIII. \(\beta\)-glucose
C. Nucleic acidI. nucleotide
D. ProteinIV. \(\alpha\)-amino acid
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